solve: -4<-3x+2<29
same way as if you were doing any other equation keep in mind you want "x" isolated so you'd need to get rid of the +2 first then get rid of the -3 so you add and divide as needed in this case you don't have a left-side and right-side you have 3 sides, left, middle and rigth any adding or subtracting or dividing, will have to occur to ALL 3 sides simultaneously
ok what would be the first step?
-4-2?
\(\bf -4<-3x+2<29\\ \textit{subtracting 2 from all 3 sides}\\ -4(-2)<-3x\cancel{+2(-2)}<29(-2) \implies -6 < -3x < 27\)
ok I understand. how do I get x by itself?
divide 3x all 3 sides?
got it
2<x<-9????
well, you want to leave the "x" by itself, so, you want to get rid of the -3 the one difference in simplifying inequalities, is that when dividing/multipliying/exponentializing by a NEGATIVE VALUE, you'd need to \(\bf \text{flip the sign}\)
that's correct, since you used -3, that is, NEGATIVE 3, then you'd need to flip the sign the other way
2<x>-9
??
do you agree
\(\bf -4<-3x+2<29\\ \textit{subtracting 2 from all 3 sides}\\ -4(-2)<-3x+2(-2)<29(-2) \implies -6 < -3x < 27\\ \textit{dividing by NEGATIVE 3}\\ 2 \color{red}{>} x \color{red}{>} -9\)
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