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What is the domain of (see more)
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f(x)=\[\sqrt{x-4}\]
its shifted right 4 so ?
Whenever you're dealing with any even root, the thing to think about is that the expression under the radical sign must be nonnegative. So you need to make sure that: \(x-4\ge0\) Just solve that inequality, and that gives you your domain.
Right, as @macknojia suggests, if you are familiar with the graph of \(y=\sqrt{x}\), and with transformations, then you can just view this as a rightward shift of that graph so you can get the domain that way. The algebraic method I suggested will work for functions where the graph might not be quite so obvious,though.
ohhh thanks so much!
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