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Can someone double check my work?
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2. \[(-3x^5)(2xy^4)(6xy)^0\] I got: \[-3x^5(2xy^4) \] \[= -6x^6y^4(1)\] \[= -6x^6y^4\] (final answer)
Also, 3. \[\left(\begin{matrix}xyz^3 \\ y^5w^-7\end{matrix}\right)\] Which I got: \[\frac{ xyz^3w^7 }{ y^5}\]
it looks good
you can subtract the y on top with bottom
Oops, there isn't supposed to be a parentheses for #3. And okay, so: \[\frac{ 1}{ xy^-5z^3w^7 } \]
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this is a new problem ?
Oh no, that was supposed to be the answer to the problem.
why did you change it ?
you had it right the only thing you have to do is subtract the y and you get xz^3w^7 -------- y^4
Oh, okay. I had subtracted 1 from 5 and got -4 and then flipped the equation. Thank you for your help.
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