Can someone double check my work?

Question

anonymous · Answer

2. $$(-3x^5)(2xy^4)(6xy)^0$$

I got: $$-3x^5(2xy^4) $$
$$= -6x^6y^4(1)$$
$$= -6x^6y^4$$ (final answer)

anonymous · Answer

Also, 

3. $$\left(\begin{matrix}xyz^3 \ y^5w^-7\end{matrix}\right)$$

Which I got: $$\frac{ xyz^3w^7 }{ y^5}$$

ivettef365 · Answer

it looks good

ivettef365 · Answer

you can subtract the y on top with bottom

anonymous · Answer

Oops, there isn't supposed to be a parentheses for #3. And okay, so:

$$\frac{ 1}{ xy^-5z^3w^7 } $$

ivettef365 · Answer

this is a new problem ?

anonymous · Answer

Oh no, that was supposed to be the answer to the problem.

ivettef365 · Answer

why did you change it ?

ivettef365 · Answer

you had it right the only thing you have to do is subtract the y and you get

xz^3w^7
--------
    y^4

anonymous · Answer

Oh, okay. I had subtracted 1 from 5 and got -4 and then flipped the equation. Thank you for your help.