Solve using the square root method. Round to the nearest tenth, if necessary.
x2 + 17 = 0

{10.7}
{-4.1, 4.1}
{-17, 17}
No real solution

Question

Solve using the square root method. Round to the nearest tenth, if necessary.
x2 + 17 = 0

    {10.7} 
   {-4.1, 4.1} 
   {-17, 17} 
   No real solution

anonymous · Answer

sorry my being slow im in 9th trying my best to get to 10th

phi · Answer

you have
$$ x^2 + 17 = 0 $$
the first step is add -17 to both sides
$$ x^2 + 17-17  = 0-17 $$
and simplify

phi · Answer

Can you simplify
$$ x^2 + 17-17  = 0-17 $$ ?

you should get
$$ x^2 = -17$$

now this is important:  there is no (real) number times itself that will be negative

phi · Answer

normally you would take the square root of both sides
$$ \sqrt{x^2} = \sqrt{-17} \ x = \sqrt{-17} $$

but x will not be a real number.

phi · Answer

if you type sq rt of -17 into your calculator, it will complain

phi · Answer

I assume you figured out the answer is "no real solution"