Question

show that two vectors are perpendicular.

Answer 1

to show that they are perpendicular the dot product should be equal to zero.
to take the dot product

Answer 2

ok so I know that. but I am just wondering if there is a simpler way. just a second I am typing out the problem.

Answer 3

I have vectors \(\mathbf{A}\) and (\mathbf{B}\) and \(|\mathbf{A}|=|\mathbf{B}\). I need to show that \(\mathbf{A}-\mathbf{B}\) is perpendicular to \(\mathbf{A}+\mathbf{B}\)

Answer 4

can you not edit your posts anymore?

Answer 5

could you take a picture of the problem somehow?

Answer 6

\[(\bar A+\bar B)·(\bar A-\bar B)=\bar A·\bar A-\bar A·\bar B+\bar B ·\bar A-\bar B·\bar B=\left| \bar A \right|^2-\left| \bar B \right|^2=0\]

Answer 7

thanks. I am rusty haha.

Answer 8

Graphically, if both vectors have the same module they outline two adjacent sides of a rhombus or a square and their diagonals (sum and difference) are always perpendicular