Question

solve for x 6-3(2x-4)=2(1+x)

Answer 1

Solve for x:
6 x-3 (2 x-4) = 2 (x+1)
Factor the polynomial, 2 x-4.
Factor 2 from the polynomial 2 x-4:
6 x-3×2 (x-2) = 2 (x+1)
Multiply -3 and 2 together.
-3×2 = -6:
6 x+-6 (x-2) = 2 (x+1)
Distribute -6 over x-2.
-6 (x-2) = 12-6 x:
6 x+12-6 x = 2 (x+1)
Group like terms in 6 x+12-6 x.
Grouping like terms, 6 x+12-6 x = 12+(6 x-6 x):
12+(6 x-6 x) = 2 (x+1)
Look for two terms that sum to zero.
6 x-6 x = 0:
12 = 2 (x+1)
Reverse the equality in 12 = 2 (x+1) in order to isolate x to the left hand side.
12 = 2 (x+1) is equivalent to 2 (x+1) = 12:
2 (x+1) = 12
Divide both sides by a constant to simplify the equation.
Divide both sides of 2 (x+1) = 12 by 2:
(2 (x+1))/2 = 12/2
Any nonzero number divided by itself is one.
2/2 = 1:
x+1 = 12/2
Reduce 12/2 to lowest terms.
The gcd of 12 and 2 is 2, so 12/2 = (2×6)/(2×1) = 2/2×6 = 6:
x+1 = 6
Isolate terms with x to the left hand side.
Subtract 1 from both sides:
x+(1-1) = 6-1
Look for two terms that sum to zero.
1-1 = 0:
x = 6-1
Evaluate 6-1.
6-1 = 5:

Answer 2

x6-3*(2*x-4)=2*(1+x) simplifies to x6-8*x+10=0