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Calculus1 7 Online
OpenStudy (anonymous):

HELP!!! integral sinh(square root of x)/square root of x

OpenStudy (anonymous):

u sub... let u = sqrt x

OpenStudy (anonymous):

\[\int\limits \frac{ \sinh \sqrt{x} }{ \sqrt{x} }\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the person is not even here!

OpenStudy (anonymous):

Help!

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

help please @phi

OpenStudy (anonymous):

@Peter14

OpenStudy (anonymous):

@Preetha

OpenStudy (anonymous):

I know u = \[\sqrt{x}\]

OpenStudy (anonymous):

@onedirection822

OpenStudy (anonymous):

@Peter14

OpenStudy (anonymous):

@Saint101

OpenStudy (anonymous):

@Falco276

OpenStudy (anonymous):

@SAM

OpenStudy (anonymous):

so what's du?

OpenStudy (anonymous):

I'll try...

OpenStudy (anonymous):

@.Sam.

OpenStudy (anonymous):

YESS MY PLAN WORKED

OpenStudy (anonymous):

indefinite integral or definite integral?

OpenStudy (anonymous):

and do you know what function sinh is?

OpenStudy (anonymous):

@Newton96 ... what is du then?

OpenStudy (anonymous):

\[u=\sqrt{x} \text{, } du = \text{ ?}\]

OpenStudy (anonymous):

du = 1/2 x^-1/2 dx

OpenStudy (anonymous):

so then what does the integral simplify to in terms of u?

OpenStudy (anonymous):

\[du = \frac{ 1 }{2\sqrt{x} }dx\] right o?

OpenStudy (anonymous):

Thank you so much for all the help, guys! But I already figured the problem out! Thanks! :-)

OpenStudy (anonymous):

\[\int\limits \frac{ \sinh \sqrt{x} }{ \sqrt{x} }dx = \int\limits \frac{ 2\sinh \sqrt{x} }{ 2\sqrt{x} }dx=2\int\limits \sinh {u} \, du\]

OpenStudy (anonymous):

okay... you're welcome

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