solve √x+11 = (√x-5) +2
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Solve for x: 11+sqrt(x) = sqrt(x)-3 Isolate sqrt(x) to the left hand side. Subtract 11+sqrt(x) from both sides: 0 = -14 Look for a false statement. 0 = -14 is trivially false: Answer: | | (no solutions)
@annalizz12:First say how can we killing the powers ?!
\[\sqrt{x+11} = \sqrt{x-5}+2\] so... \[x ^{2}+11^{2} = x ^{2} -5^{2}+2\]?
Exacly ! Now but remeber alway the x s are in a place and numbers are in another place ! It s better !
so where do i go from there..
Look : we have : x+121=x+25+2 x-x=121+27 So the question has no solutions !
ok thanks!
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