Question

Find an equation for the line tangent to y=4-(4x)^2 at the point (3, -32)

Answer 1

find the slope M

Answer 2

By doing this we solve for y and x

Answer 3

I know i should do that but I kinda forgot how to work that out

Answer 4

In this case \(a = 3, f(a)= -32\).

Answer 5

\[
f(x) - f(a) = f'(a)(x-a)
\]

Answer 6

Then use point slope formula to obtain the equation of the tangent line.

Answer 7

The line \(y\) which is tangent to \(f(x)\) at point \( (a,f(a))\) is given by:\[
y - f(a) = f'(a)(x-a)
\]