Question

when the expression x^3+mx^2+nx-5 is divided by x+2 and x+3, the remainder are 2 and 13 respectively. Find the values m and n

Answer 1

@Coolsector pls help again :)

Answer 2

so it is the same problem
p(x) = x^3+mx^2+nx-5
so
p(-2) = 2
p(-3) = 13

Answer 3

but i really want you to understand why and how to write those two :
p(-2) = 2
p(-3) = 13

Answer 4

p(-2) because x+2=0 transpose x=-2 p(-3) because x+3=0 x=-3

Answer 5

ok:)

Answer 6

ive got the answers 4m-2=15 and 9m-3n=45 is that correct?

Answer 7

i guess you meant 4m-2n=15

Answer 8

yup

Answer 9

so yes :)

Answer 10

value of m is 6? pls check

Answer 11

i dont know, you can find n now and then check them both together with the initial equations :
p(-2) = 2
p(-3) = 13