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OpenStudy (anonymous):
draw a graph of the function and indicate the average value
\[f(x)=x ^{3}-5x ^{2}+10; \left[ 0,4 \right]\]
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OpenStudy (anonymous):
average value is
\[\frac{f(4)-f(0)}{4-0}\]
OpenStudy (anonymous):
don't I use the anti-derivative of the function?
OpenStudy (anonymous):
oh i see you want
\[\frac{1}{4}\int_0^4(x^3-5x+10)dx\]
OpenStudy (anonymous):
aka "mean value" right
OpenStudy (anonymous):
yes I believe that is what the question calls for
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OpenStudy (anonymous):
ok
the "anti derivative" is not too bad because this is a polynomial
it is
\[\frac{x^4}{4}-\frac{5x^2}{2}+10x\]
OpenStudy (anonymous):
(5x^3)/3 right
OpenStudy (anonymous):
plug in 4
ignore 0 because that just gives you 0
then divide by 4
OpenStudy (anonymous):
right i did all that. i got approx. -.75. does that seem correct?
OpenStudy (anonymous):
it is \(-5x\) or \(-5x^2\) ?
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OpenStudy (anonymous):
-5x^2
OpenStudy (anonymous):
oooh ok
OpenStudy (anonymous):
then no it is \(-\frac{2}{3}\)
OpenStudy (anonymous):
ok i get that. But how would they go on the graph. Could you give me a crude drawing?
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OpenStudy (anonymous):
and the average value represented on the graph would just be a straight line at -2/3?
OpenStudy (anonymous):
that i do not know
sorry
OpenStudy (anonymous):
ok thank you
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