How do you solve an indicated variable like 5y+2x=15 when y is the variable you need to solve for?
algebra everything else to one side ...
do you know how to solve an equation that has only 1 variable?
Yes I do. But I was wondering if I'm supposed to divide the 5 at the same time I divide the 2x
you cant really do two things at once here ... its just not that practical tell me why you think you need to divide a 2x?
Well to solve for an indirect variable, you need to get that vaiable alone on one side. So if I was to get y on one side of the equal sign, then wouldn't I have to separate it from the 5 it's attached to? As well as the 2x? so the 5, 2x, and 15 would all some how equal y...
if we work this step by step, not necessarily in this order ... but this is good enough 5y + 2x = 15 , to get rid the +2x, we subtract 2x from each side - 2x -2x ------------- 5y + 0x = 15 - 2x , simplfy the zero part 5y = 15 - 2x , now that we have a single term in y, we can now divide off that 5 /5 /5 ------------- 1y = (15-2x)/5 y = (15-2x)/5 , and simplfy to your hearts content
oh wow, I COMPLETELY forgot that we had to do the opposite operation... so I was going to divide the 2x. Ugh first day of school review packet of something I did over 2 years ago without going over any of it isn't the best idea. why they put algebra 1, then geometry, then algebra 2 in that order, I'll never know. thanks for the help!
:) good luck
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