Question

Can someone check my work please?
Its Rearranging Equations.

Answer 1

try your #5 again

Answer 2

Okay. Anything else?

Answer 3

dunno, i just got to the end of reading the sideways one ...

Answer 4

ah ok

Answer 5

Uhm...I got the same answer for #5. Could you walk me through after you are done checking?

Answer 6

pfft, they are both sides ways ... You seem to be dividing off a +2x in #5 ,,, when there is no multiplication to be undone

Answer 7

500 = 2x + y, solve for y

Answer 8

you did the same mistake in #7

Answer 9

and #8

Answer 10

and #10

Answer 11

youve made the same mistakes in those problems

Answer 12

for example:

14 = 6 + 8

14/6 = 8 is wrong ...

Answer 13

instead of dividing, what should we have done?

Answer 14

OHHH!!!!!
SUBTRACTION FOR THE WIN!!!
Lemme get straight to work on that sir!

Answer 15

:)

Answer 16

Makes sense as to why I was like,"Those answers are weird."

Answer 17

So I think I got it..
#5= 500x-2x^2
#7= 108x^2-4x^3
#8=22x^3
#9= \[\frac{ 3w ^{2- w} }{ 2 }\]

Answer 18

That w is not a part of the exponent btw..

and Thats 10. not 9 lol

Answer 19

@amistre64 You there?

Answer 20

y = 500 -2x
A = x(500-2x) good

y = 108 - 4x
V = x^2(108-4x) good

4xy = 100-2x^2
2xy = 50- x^2
y = 25/x -x/2
V = x^2(25/x - x/2)
V = 25x - x^3/2 , rechk your #8

Answer 21

4wh = 3 - 2w^2
h = (3 - 2w^2)/w
V = w^2 (3-2w^2)/w
V = w (3-2w^2) rechk that one too #10

Answer 22

lost a 4 ...

Answer 23

Can't 50/2x=25x?

Answer 24

x^2(50/2x) = 25x yes but thats only part of it

Answer 25

Right. But in one or your steps for #8 you wrote 25/x. How did you get that? Could you walk me through number 8?

Answer 26

4xy = 100-2x^2 ; divide by 2, not needed but was something I did

2xy = 50- x^2 , divide by 2x and simplfy
/2x /2x /2x
--------------
y = 25/x -x/2

V = x^2(25/x - x/2)
V = 25x - x^3/2 , rechk your #8

Answer 27

Seee!!!!
U wrote 50/2x and made it equal to 25/x. Thats different from 25x.

Answer 28

i plugged y into V

Answer 29

lets ignore the simplification ....

4xy = 100-2x^2 ; divide by 4x

y = (100-2x^2)/4x

V = x^2(100-2x^2)/4x
V = x(100-2x^2)/4

Answer 30

now when we simplify ...

x(100-2x^2)/4

(100x-2x^3)/4

100x/4 - 2x^3/4

25x - x^3/2

Answer 31

I got lost..hm. Can I show you how I solved it?

Answer 32

HOLD UP.
I GOT IT.

Answer 33

Except for the fact.

Answer 34

That I got a 25x^3

Answer 35

not a reg 25x

Answer 36

on number 10. Wouldn't that all be over 4?

Answer 37

@KingGeorge Could you confirm for me on number 10?

Answer 38

and 9.

Cuz I am just completely rooted and stuck

Answer 39

Let's start with 10. You start with \[3=2w^2+4wh,\]and want to solve for \(h\). The first thing you need to do is \(\bf subtract\) \(2w^2\) instead of dividing. So that will get you \[3-2w^2=4wh.\]Following me so far?

[If you divide you get \(3/(2w^2)=1+2h/w\)]

Answer 40

So long story short, #10 needs some fixing. But #9 looks correct to me.

Answer 41

Wait. So. hold on start with 9. I is correct, what would be the answer then? Cuz I got like 3 different ones from resolving. Is it the one on the screenshot?

Answer 42

and yes following you on number 10.

Answer 43

The one in the screenshot seems correct to me for 9.

The next step in 10, is to divide by \(4w\). This will get you\[\frac{3-2w^2}{4w}=\frac{3}{4w}-\frac{w}{2}\]

Answer 44

ok.

Answer 45

Understood that..

Answer 46

So that's your equation for \(h\). Plug that in, and you get\[V=w^2\left(\frac{3}{4w}-\frac{w}{2}\right)=\frac{3w}{4}-\frac {w^3}2\]

Answer 47

I ended up with a w^3 at the end. not w^2

Answer 48

Did u cross stuff out?

Answer 49

I have a w^3 at the end, and not a w^2....

Answer 50

ohh ok! YESSSSS I GET IT!!!

Although then..did Amistre mess up on #9?

Answer 51

I don't think amistre ever mentioned 9.

Answer 52

Oh i meant 8!!

Answer 53

What do u think on that one?

Answer 54

Cuz. I have seen different ways of solving :/