f(x)= 3/x+6
g(x)=x^2-3
find(f/g)(x)

Question

anonymous · Answer

$$f(x)=\frac{ 3 }{ x+6 }$$
and
$$g(x) =x^{2}-3$$
?????

anonymous · Answer

yes thats it

jdoe0001 · Answer

$\bf \left(\cfrac{f}{g}\right)x \implies \cfrac{f(x)}{g(x)}\
\textit{keep in mind that } \cfrac{\frac{a}{b}}{\frac{c}{d}} \implies \cfrac{a}{b}\implies\cfrac{d}{c}$

anonymous · Answer

i know how its set up i just dont know how to solve

jdoe0001 · Answer

ohh ... darn.. .I have a typo

jdoe0001 · Answer

$\bf \left(\cfrac{f}{g}\right)x \implies \cfrac{f(x)}{g(x)}\
\textit{keep in mind that } \cfrac{\quad\frac{a}{b}\quad }{\frac{c}{d}} \implies \cfrac{a}{b}\times\cfrac{d}{c}$

anonymous · Answer

$$\frac{ f(x) }{g(x) } = \frac{ \frac{ 3 }{x + 6 } }{ x ^{2}-3 } = \frac{ 3 }{(x+6)(x ^{2}-3) }$$

anonymous · Answer

same thing jdoe0001

anonymous · Answer

so i should end up with $$\frac{ 3 }{ x ^{3}+6x ^{2}-3x-18 }$$

anonymous · Answer

it's ok