Question

f(x)= 3/x+6
g(x)=x^2-3
find(f/g)(x)

Answer 1

\[f(x)=\frac{ 3 }{ x+6 }\]
and
\[g(x) =x^{2}-3\]
?????

Answer 2

yes thats it

Answer 3

\(\bf \left(\cfrac{f}{g}\right)x \implies \cfrac{f(x)}{g(x)}\\
\textit{keep in mind that } \cfrac{\frac{a}{b}}{\frac{c}{d}} \implies \cfrac{a}{b}\implies\cfrac{d}{c}\)

Answer 4

i know how its set up i just dont know how to solve

Answer 5

ohh ... darn.. .I have a typo

Answer 6

\(\bf \left(\cfrac{f}{g}\right)x \implies \cfrac{f(x)}{g(x)}\\
\textit{keep in mind that } \cfrac{\quad\frac{a}{b}\quad }{\frac{c}{d}} \implies \cfrac{a}{b}\times\cfrac{d}{c}\)

Answer 7

\[\frac{ f(x) }{g(x) } = \frac{ \frac{ 3 }{x + 6 } }{ x ^{2}-3 } = \frac{ 3 }{(x+6)(x ^{2}-3) }\]

Answer 8

same thing jdoe0001

Answer 9

so i should end up with \[\frac{ 3 }{ x ^{3}+6x ^{2}-3x-18 }\]

Answer 10

it's ok