f(x)= 3/x+6
g(x)=x^2-3
find[gxf](x)

Question

f(x)= 3/x+6
g(x)=x^2-3
find[gxf](x)

tkhunny · Answer

Did you mean $f(x) = \dfrac{3}{x} + 6$?  That's what you wrote.

anonymous · Answer

$$f(x)=\frac{ 3 }{x+6}                      $$

tkhunny · Answer

Parentheses are wonderful things:  f(x) = 3/(x+6).  You must see the difference.

We seek g(f(x))?

anonymous · Answer

sorry... and yes that's what I'm looking for.

tkhunny · Answer

It's never a matter of "sorry".  We're all learning.

Can you evaluate g(7) = ?

anonymous · Answer

the questions wants me to just find the g(f(x)) not an input value

tkhunny · Answer

You didn't answer my question.  Evaluate g(7).

anonymous · Answer

g(7)=46

tkhunny · Answer

How did you get that?  Like this: g(7) = 7^2 - 3 = 49 - 3 = 46?

You had g(x).  When you moved to g(7), what did you do?

Whatever you did, why would it be any different for g(4) or g(12) or g(Whale) or g(f(x))?  Do EXACTLY the same thing with f(x) as you did with 7.  EXACTLY!