Question

isolate the a

d=v*t+1/2*a*t^2

Answer 1

step 1. subtract vt on both sides
step 2. multiply both sides by 2 to get rid of 1/2
step 3. divide by \[t^2\]

Answer 2

vt is being multiplied can we still subtract it? how about we just divide the other side by t and then subtract v1

Answer 3

here's what i got:

2d-v1/t/t^2 = a

Answer 4

it's another method of doing it dividing by t leaving you v+1/2*a*t then you subtract v and divide t multiply by 2.

Answer 5

however, in your case the math you did was wrong due to dividing t and dividing t^2 again leaving the denominator with t^3 where we do not even have t^3 to begin with

Answer 6

a=2d-v/t^2 is the answer that i got.

Answer 7

let me confirm

Answer 8

you forgot to multiply t. or you forgot to put them seperate after you canceled one t

Answer 9

the correct answer should be a= (2d-2vt)/t^2 or a= 2d/t^2-(2v/t)

Answer 10

2 is only multiplied with the numerator right? and if so do we only multiply d and v or d,v and t?

Answer 11

(2(d-vt))/(t^2) = a