Find the average value for the length of an object with uncertainty if the 5 measurements are 87.5 cm, 88.0, 86.9 cm, 87.7cm and 88.0cm.
Average value:
Standard deviation:
Standard error:

Therefor, the average value with uncertainty is:___

how to do this?
can i add them and divide them by 5?
how about the second and 3rd question?

Question

Find the average value for the length of an object with uncertainty if the 5 measurements are 87.5 cm, 88.0, 86.9 cm, 87.7cm and 88.0cm.
Average value:
Standard deviation:
Standard error:

Therefor, the average value with uncertainty is:___

how to do this?
can i add them and divide them by 5?
how about the second and 3rd question?

luigi0210 · Answer

Oh, I used to be so good at this.. err

anonymous · Answer

oh, so you can help me?? (^_^)

luigi0210 · Answer

Oh how I wish I could data :/

luigi0210 · Answer

Does this have anything to do with linear approximation and differentials?

luigi0210 · Answer

>.>

loser66 · Answer

hehe, mistypo, I am sorry,

loser66 · Answer

standard deviation is 87.45
standard error is 0.55
average value with uncertainty is 87.62

anonymous · Answer

how did you get that?

loser66 · Answer

standard deviation: (first + last)/2
standard error (last - first )/2
average (sum of 5 terms )/5

loser66 · Answer

first means the least, last means the biggest number

anonymous · Answer

ahhhhh....thank you very much:)