What is the equation of the line in standard form that passes through the point (–2, –3) and is parallel to the line y = x + 9?

Question

anonymous · Answer

Well, we know the equation for a line is  $y=mx+b$ Where $m$ is its slope and $b$ is the y-intercept. We also know that if Line A has a slope of $m_1$ and Line B has a slope of $m_2$, and Line A is parallel to Line B, then $m_1=m_2$. So we can develop some things from here.

One thing is that we know the mentioned line, has a formula of $y=x+9$; from that, we can deduce that it has a slope of $1$ and therefore, our line must also have a slope of $1$ since they are parallel

anonymous · Answer

So the formula for our line is:
$$y=(1)x+b=x+b$$

We can sub in a point we know:
$$-3=-2+b$$
And solve for $b$
$$b=-3+2=-1$$
So the formula would be
$$y=x-1$$

anonymous · Answer

A. x – y = 1

B. x + y = 1

C. x – y = –5

D. x + y = –5

are my answers to choose from

anonymous · Answer

First, find the slope of the equation of $$y = x + 9$$ by using your slope-intercep form: $$y = mx + b$$.  In this case, m = 1.  Using the point slope formula $$(y-y1) = m(x-x1)$$  Use this formula to plug in the numbers that have been provided.  Points (-2,-3) and m = 1.  Then solve for y.

anonymous · Answer

Oh okay well,
$$y=x-1$$
$$y-x=-1$$
$$-(y-x)=1$$
$$x-y=1$$
So the equation is A

anonymous · Answer

Thank you bunches!! =)

anonymous · Answer

Anytime :)