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Differentiate: y=5^(3x)
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Do you take the natural log of each side?
You know that \[\frac{d}{dx}a^x=a^x\ln{a}\]right? And you can rewrite \(5^{3x}\) as \((5^3)^x\).
I got y'=5^(3x)*(ln5)
There's something missing there.
Yeah its suppose to be 3ln5, but does that 3 come from when you take the derivative of 3x?
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Yep, that's what you get when you apply the chain rule.
thank you! How do you simplify dy/dx= y(2+2lnx)
What do you mean by simplify?
The next step.. The problem is y=x^(2x)
You plug in y=x^(2x) into the equation for dy/dx.
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Seriously!? I've been here over thinking this. Thanks so much
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