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if a ball is tossed from ground level upward at a speed of 44 m/s how long will it take to reach its maximum height
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H=V^2/(2*g)=44^2/(2*10)= 96.8 Not considering the air friction
@ellina so 96 seconds?
t=v/g=44/10=4.4s in 4.4 seconds
@ellina what is that first equation for? sorry im confused
nevermind
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@ellina where did you get 96.8 then 4.4 seconds
you are asking the max height 96.8 meter is the height
and it takes only 4.4 second to get that height
OK , I didn't read the problems seriously,sorry
@ellina the other part is .. how long will it take to return to ground level (the time for entire trip)
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then ,you will use the max height to caculate the rest time t=sqrt{2 times H div g}=sqrt{2times96.8div10}
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