Adding and Subtracting Radical Expressions
\[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\]
If someone simplified \[-10x \sqrt{2x}\] what did he do wrong?
can you facotrise 8 , and 18 so that one of the factors is a square number ?
You could simplify 8 to be \[2\sqrt{2}\] and 18 could be simplified to \[3\sqrt{2}\]
yeah thats right
My question is that it asks me that if someone got \[-10x \sqrt{2x}\] what did he do wrong when simplifying?
so can you tell me the correct simplification?
\[3\sqrt{2x}+2x \sqrt{2x}-3\sqrt{2x}\]
The first and last would cancel each other out so you would be left with the one in the middle.
dont forget, the last term had a co-efficient of 5 \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] \[=3\sqrt{2x}+2x \sqrt{2x}-5\times3\sqrt{2x}\]
oh yea :P
\[3\sqrt{2x}+2x \sqrt{2x}-15\sqrt{2x}\] \[-12\sqrt{2x}+2x \sqrt{2x}\]
Thats it, now if you compair with 'someone's answer, maybe they forgot a factor
Could it be that they added the 2 as well even though its not a like term?
yeah, i think they may have forgot this x , and hence added the terms \[-12\sqrt{2x}+2\color{gray}x \sqrt{2x}\]
oh I see thank you :)
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