Construct a truth table to show that the conditional is equivalent to ~p v q.
I guess I don't fully understand the truth values of the terms well enough to fill these out properly. Too much uncertainty on my part, so hoping someone can explain, lol.
do you know the truth table for \(p\to q\)?
Not sure. I can take a guess but Im not positive about it.
the first step is to write all combinations of T and F for \(p\) and \(q\) usually it is written line this \[\begin{array}{|c|c|c} p & q & p\to q \\ \hline T & T & \\ T & F & \\ F & T & \\ F & F & \\ \hline \end{array}\]
so in each row, there is a combination of T and F for example in the second row, \(p\) is True and \(q\) is False
\[p \rightarrow q\] |dw:1378394832502:dw| Im pretty sure I remember false implying true but I never understood why. Although I could be confusing that with another implication, I forget
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