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Mathematics 11 Online
OpenStudy (psymon):

Construct a truth table to show that the conditional is equivalent to ~p v q.

OpenStudy (psymon):

I guess I don't fully understand the truth values of the terms well enough to fill these out properly. Too much uncertainty on my part, so hoping someone can explain, lol.

OpenStudy (anonymous):

do you know the truth table for \(p\to q\)?

OpenStudy (psymon):

Not sure. I can take a guess but Im not positive about it.

OpenStudy (anonymous):

the first step is to write all combinations of T and F for \(p\) and \(q\) usually it is written line this \[\begin{array}{|c|c|c} p & q & p\to q \\ \hline T & T & \\ T & F & \\ F & T & \\ F & F & \\ \hline \end{array}\]

OpenStudy (anonymous):

so in each row, there is a combination of T and F for example in the second row, \(p\) is True and \(q\) is False

OpenStudy (psymon):

\[p \rightarrow q\] |dw:1378394832502:dw| Im pretty sure I remember false implying true but I never understood why. Although I could be confusing that with another implication, I forget

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