Question

Can someone tell me if I'm correct? VERY MUCH APPRECIATED
(-1)(x^2) - 3/2x^69 - square root of 2.4 IS a polynomial.

1(x^2) - 3x^69/2 IS a polynomial.

(-1)(x^2) - 3x^68 - square root of 2.4(x) IS a polynomial.

1(x^2) - 3x^69 - square root of x IS a polynomial.

1(x^2) - 3x^-96 IS NOT a polynomial.

Answer 1

give your reasoning ....

Answer 2

or, how would you define a polynomial?

Answer 3

To be honest I was guessing. I know polynomials can't have a negative exponent or a variable as a denominator ?

Answer 4

good, they also cant have anyting like square roots and such of a variable ....

if memory serves, the coefficients are not restricted tho, or are they?

Answer 5

and for "square root of", just type sqrt(x) its more readily understood

Answer 6

(-1)(x^2) - 3/2x^69 - sqrt(2.4)
^ ^
is this under the fraction?


1(x^2) - 3x^69/2
^ ^
good


(-1)(x^2) - 3x^68 - square root of 2.4(x)
is this sqrt(2.4x) ? or, x sqrt(2.4)?

1(x^2) - 3x^69 - sqrt(x)
^^
trouble

1(x^2) - 3x^-96
^^
trouble

Answer 7

hopefully that second one isnt x^(69/2)

Answer 8

the ^69 is over the 3/2

Answer 9

it's 2.4 times x

Answer 10

\[\frac32x^{69} \text{ is a good term then}\]

Answer 11

the the x is getting sqrted, then theres trouble

Answer 12

*if the x is getting ..

Answer 13

so the first on IS a polynomial?

Answer 14

if ive read your post correctly, then the first one looks fine

Answer 15

Here, can I take a screen shot of the question and attach it? would that be easier?

Answer 16

that would be fine

Answer 17

Ok give me a minute please and thank you :D

Answer 18

much better :)

Answer 19

I figured as much

Answer 20

now, from the information ive already stated; can you tell me (by number) which ones you beleieve to be polys?

Answer 21

1, 2, and 4 I believe

Answer 22

spose by letter is fine .... dint see them there for some reason :)

Answer 23

maybe 3

Answer 24

does 2 have a fraction as an exponent on the x?

Answer 25

Yes.

Answer 26

does 69/2 simplify to an integer?

Answer 27

So it isn't a poly

Answer 28

69 is like 34. something ?

Answer 29

then its not an integer result and is bad for poly definitions

Answer 30

so b is NOT a poly

Answer 31

b is NOT a poly

Answer 32

... too many options

for D, can a poly have a sqrt(x) in it?

Answer 33

Yes

Answer 34

? I think lol

Answer 35

\[\Large\sqrt x =x^{1/2}\]
can we have exponents that are not integers?

Answer 36

just remember that if x has anything other than an exponent and a coefficient acting on it, its bad news

Answer 37

sin(x) is bad news

ln(x) is bad news

e^(x) is bad news

sqrt(x) is bad news

if the exponents is not a positive integer, ... its bad news as well

Answer 38

from this, I can only see 2 options that are polynomials by definition

Answer 39

\[(-1)\cdot x^2-\frac32x^{69}-\sqrt{2.4}~;~good \]
\[1\cdot x^2-3\cancel {x^{69/2}}\]
\[(-1)\cdot x^2-3 {x^{68}}-\sqrt{2.4}\cdot x~:~good\]
\[1\cdot x^2-3 {x^{69}}-\cancel{\sqrt{x}}\]
\[1\cdot x^2-3 \cancel{{x^{-69}}}\]

Answer 40

So is it A and D?

Answer 41

uh, no.

its A and C ... barring any typos that is

Answer 42

Ohh ok. Well thank you you've really helped a lot

Answer 43

youre welcome, and good luck :)