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8^2 x 8^-5
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\[x^n\times x^m=x^{n+m}\]
how would I get that into correct simplication? I don't understand
well x=8 n=2 m=-5
Oh okay. I understand! Thank you!
what do you get as a final answer?
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64^7?
is that correct?
nope
ok
when there is a multiplication of terms with the same base, you have to add the indicies 8^2 x 8^-5 = 8^{2-5} =
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8^3?
almost
8^7?
what is 2 - 5 ?
-3
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yeah
okay
so 8^{2-5} =
8^-3?
yes,
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when you have some term with a negative index, say \(A^{-p}\) its the same as \(\dfrac1{A^p}\)
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