Mathematics
7 Online
OpenStudy (anonymous):
Geometry question, picture attached, help?
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910 can you help?
jimthompson5910 (jim_thompson5910):
if you have 2 points x and y on a number line, then the midpoint is
(x+y)/2
OpenStudy (anonymous):
So the midpoint is 7?
jimthompson5910 (jim_thompson5910):
-2+12 is NOT 14
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OpenStudy (anonymous):
My bad it's 10 so the midpoint is 5?
jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
So 5 is the answer, correct?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
Can you help with 2 more questions?
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jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
solve for x
(x+ 5)/2 = -1
then solve for y
(y+2)/2 = 0
OpenStudy (anonymous):
Im confused. how do i solve for x?
jimthompson5910 (jim_thompson5910):
(x+ 5)/2 = -1 ... Start with the given equation
x+5 = -1*2 ... Multiply both sides by 2.
x+5 = -2 ... Multiply
x = ???
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OpenStudy (anonymous):
x is 10?
jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
2 times 5?
jimthompson5910 (jim_thompson5910):
what undoes addition?
OpenStudy (anonymous):
subtraction
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jimthompson5910 (jim_thompson5910):
yep
OpenStudy (anonymous):
so 3?
jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
im so confused
jimthompson5910 (jim_thompson5910):
-2 - 5 = ???
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OpenStudy (anonymous):
oh ok, -7?
jimthompson5910 (jim_thompson5910):
so x = -7
OpenStudy (anonymous):
ok and do the same thing for y?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
y=-4?
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OpenStudy (anonymous):
Ok thanks so much! One more question?
jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
Last question.
jimthompson5910 (jim_thompson5910):
are you familiar with the distance formula?
OpenStudy (anonymous):
No i am not, sorry my connection keeps going out.
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jimthompson5910 (jim_thompson5910):
that's ok
jimthompson5910 (jim_thompson5910):
to learn about the distance formula
OpenStudy (anonymous):
Will the distance formula be needed for this problem?
jimthompson5910 (jim_thompson5910):
yes it will
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OpenStudy (anonymous):
Ok one moment im gonna read that page.
jimthompson5910 (jim_thompson5910):
alright
OpenStudy (anonymous):
Ok i see the distance formula.
jimthompson5910 (jim_thompson5910):
that's good
OpenStudy (anonymous):
Ok im gonna try and work this problem out, will you correct me if im wrong?
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jimthompson5910 (jim_thompson5910):
sure I can do that
OpenStudy (anonymous):
im gonna work it out in worpad and copy and paste it here.
jimthompson5910 (jim_thompson5910):
that sounds great
OpenStudy (anonymous):
This is as far as i got
d=sqrt(6-(-4))^2 + (1- (3))^2
= (6+4)^2 + (1+3)^2
OpenStudy (anonymous):
good so far?
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OpenStudy (anonymous):
I forgot to put sqrt for the second part.
jimthompson5910 (jim_thompson5910):
1-3 is not the same as 1+3
OpenStudy (anonymous):
On the page you told me to look at the second part switched the addition.
jimthompson5910 (jim_thompson5910):
the only reason why there was a sign change was because it wrote 1 - (-2)
jimthompson5910 (jim_thompson5910):
that's the same as 1 + 2
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OpenStudy (anonymous):
ok, let me correct that in wordpad, one moment
OpenStudy (anonymous):
Ok this is what i got.
d=sqrt(6-(-4))^2 + (1- (3))^2
=sqrt (6-4)^2 + (1-3)^2
=sqrt(2)^2 + (-2)^2
=sqrt4+-4=sqrt8
OpenStudy (anonymous):
right or wrong?
jimthompson5910 (jim_thompson5910):
that's incorrect
jimthompson5910 (jim_thompson5910):
6-(-4) is the same as 6+4
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jimthompson5910 (jim_thompson5910):
1-(3) is just 1-3 = -2
OpenStudy (anonymous):
Ok hold on.
OpenStudy (anonymous):
d=sqrt(6-(-4))^2 + (1- (3))^2
=sqrt (6+4)^2 + (1-3)^2
=sqrt(10)^2 + (-2)^2
=sqrt100+-4=sqrt104
Is this now correct?
jimthompson5910 (jim_thompson5910):
good, you can simplify that radical
OpenStudy (anonymous):
How do i do that? I have to round to the nearest tenth, too?
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jimthompson5910 (jim_thompson5910):
oh no need to find the exact simplified answer
just checked the instructions again and all they want is an approximate answer
jimthompson5910 (jim_thompson5910):
so just type sqrt(104) into the calculator
OpenStudy (anonymous):
ok, thats it? Even though it asks to round to the nearest tenth?
jimthompson5910 (jim_thompson5910):
yes remember to round as well
jimthompson5910 (jim_thompson5910):
what is sqrt(104) equal to?
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OpenStudy (anonymous):
My calculator doesn't have a sqrt button?
jimthompson5910 (jim_thompson5910):
sqrt stands for "square root"
jimthompson5910 (jim_thompson5910):
look for the square root symbol
OpenStudy (anonymous):
I know, i'm using a ipod calculator, it doesn't have the sqrt symbol, i googled it though and it said this 10.1980390272
jimthompson5910 (jim_thompson5910):
good, google works too
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jimthompson5910 (jim_thompson5910):
that rounds to what
OpenStudy (anonymous):
10.2?
jimthompson5910 (jim_thompson5910):
very good
OpenStudy (anonymous):
10.2 is the answer of the whole problem, right?
jimthompson5910 (jim_thompson5910):
yes it is
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OpenStudy (anonymous):
Ok thanks. i have one more questions. When constructing a an angle bisector, why must the arcs intersect?
jimthompson5910 (jim_thompson5910):
is that all it asks?
jimthompson5910 (jim_thompson5910):
or is there more to it?
OpenStudy (anonymous):
The last one is the one i just posted about the angles. ^^^
OpenStudy (anonymous):
for 100 + -4 im getting 96 now instead on 104?
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jimthompson5910 (jim_thompson5910):
it should be 100 + 4 = 104
jimthompson5910 (jim_thompson5910):
not sure how you 100 + -4
OpenStudy (anonymous):
so that 4 shouldn't be a negative? and i got it from (-2)^2 =-4
OpenStudy (anonymous):
and i got that from 1-3^2
jimthompson5910 (jim_thompson5910):
(-2)^2 is positive 4, not negative 4
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OpenStudy (anonymous):
Sorry, my mistake. Did you see the other question i posted?
OpenStudy (anonymous):
Also i got that -4 from a calulator, it keeps saying (-2)^2 is -4
jimthompson5910 (jim_thompson5910):
that's because you said -2^2
you should explicitly type in the parenthesis to say (-2)^2 = 4
OpenStudy (anonymous):
Oh ok, i got it now. Did you see the other question?
OpenStudy (anonymous):
Is it because of the vertex?
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jimthompson5910 (jim_thompson5910):
I think it's because the two arcs must intersect to form that new point that's needed to draw the angle bisector