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Mathematics 7 Online
OpenStudy (anonymous):

Geometry question, picture attached, help?

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910 can you help?

jimthompson5910 (jim_thompson5910):

if you have 2 points x and y on a number line, then the midpoint is (x+y)/2

OpenStudy (anonymous):

So the midpoint is 7?

jimthompson5910 (jim_thompson5910):

-2+12 is NOT 14

OpenStudy (anonymous):

My bad it's 10 so the midpoint is 5?

jimthompson5910 (jim_thompson5910):

good

OpenStudy (anonymous):

So 5 is the answer, correct?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

Can you help with 2 more questions?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

solve for x (x+ 5)/2 = -1 then solve for y (y+2)/2 = 0

OpenStudy (anonymous):

Im confused. how do i solve for x?

jimthompson5910 (jim_thompson5910):

(x+ 5)/2 = -1 ... Start with the given equation x+5 = -1*2 ... Multiply both sides by 2. x+5 = -2 ... Multiply x = ???

OpenStudy (anonymous):

x is 10?

jimthompson5910 (jim_thompson5910):

no

OpenStudy (anonymous):

2 times 5?

jimthompson5910 (jim_thompson5910):

what undoes addition?

OpenStudy (anonymous):

subtraction

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

so 3?

jimthompson5910 (jim_thompson5910):

no

OpenStudy (anonymous):

im so confused

jimthompson5910 (jim_thompson5910):

-2 - 5 = ???

OpenStudy (anonymous):

oh ok, -7?

jimthompson5910 (jim_thompson5910):

so x = -7

OpenStudy (anonymous):

ok and do the same thing for y?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

y=-4?

OpenStudy (anonymous):

Ok thanks so much! One more question?

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

Last question.

jimthompson5910 (jim_thompson5910):

are you familiar with the distance formula?

OpenStudy (anonymous):

No i am not, sorry my connection keeps going out.

jimthompson5910 (jim_thompson5910):

that's ok

jimthompson5910 (jim_thompson5910):

I recommend you reading this page http://www.purplemath.com/modules/distform.htm

jimthompson5910 (jim_thompson5910):

to learn about the distance formula

OpenStudy (anonymous):

Will the distance formula be needed for this problem?

jimthompson5910 (jim_thompson5910):

yes it will

OpenStudy (anonymous):

Ok one moment im gonna read that page.

jimthompson5910 (jim_thompson5910):

alright

OpenStudy (anonymous):

Ok i see the distance formula.

jimthompson5910 (jim_thompson5910):

that's good

OpenStudy (anonymous):

Ok im gonna try and work this problem out, will you correct me if im wrong?

jimthompson5910 (jim_thompson5910):

sure I can do that

OpenStudy (anonymous):

im gonna work it out in worpad and copy and paste it here.

jimthompson5910 (jim_thompson5910):

that sounds great

OpenStudy (anonymous):

This is as far as i got d=sqrt(6-(-4))^2 + (1- (3))^2 = (6+4)^2 + (1+3)^2

OpenStudy (anonymous):

good so far?

OpenStudy (anonymous):

I forgot to put sqrt for the second part.

jimthompson5910 (jim_thompson5910):

1-3 is not the same as 1+3

OpenStudy (anonymous):

On the page you told me to look at the second part switched the addition.

jimthompson5910 (jim_thompson5910):

the only reason why there was a sign change was because it wrote 1 - (-2)

jimthompson5910 (jim_thompson5910):

that's the same as 1 + 2

OpenStudy (anonymous):

ok, let me correct that in wordpad, one moment

OpenStudy (anonymous):

Ok this is what i got. d=sqrt(6-(-4))^2 + (1- (3))^2 =sqrt (6-4)^2 + (1-3)^2 =sqrt(2)^2 + (-2)^2 =sqrt4+-4=sqrt8

OpenStudy (anonymous):

right or wrong?

jimthompson5910 (jim_thompson5910):

that's incorrect

jimthompson5910 (jim_thompson5910):

6-(-4) is the same as 6+4

jimthompson5910 (jim_thompson5910):

1-(3) is just 1-3 = -2

OpenStudy (anonymous):

Ok hold on.

OpenStudy (anonymous):

d=sqrt(6-(-4))^2 + (1- (3))^2 =sqrt (6+4)^2 + (1-3)^2 =sqrt(10)^2 + (-2)^2 =sqrt100+-4=sqrt104 Is this now correct?

jimthompson5910 (jim_thompson5910):

good, you can simplify that radical

OpenStudy (anonymous):

How do i do that? I have to round to the nearest tenth, too?

jimthompson5910 (jim_thompson5910):

oh no need to find the exact simplified answer just checked the instructions again and all they want is an approximate answer

jimthompson5910 (jim_thompson5910):

so just type sqrt(104) into the calculator

OpenStudy (anonymous):

ok, thats it? Even though it asks to round to the nearest tenth?

jimthompson5910 (jim_thompson5910):

yes remember to round as well

jimthompson5910 (jim_thompson5910):

what is sqrt(104) equal to?

OpenStudy (anonymous):

My calculator doesn't have a sqrt button?

jimthompson5910 (jim_thompson5910):

sqrt stands for "square root"

jimthompson5910 (jim_thompson5910):

look for the square root symbol

OpenStudy (anonymous):

I know, i'm using a ipod calculator, it doesn't have the sqrt symbol, i googled it though and it said this 10.1980390272

jimthompson5910 (jim_thompson5910):

good, google works too

jimthompson5910 (jim_thompson5910):

that rounds to what

OpenStudy (anonymous):

10.2?

jimthompson5910 (jim_thompson5910):

very good

OpenStudy (anonymous):

10.2 is the answer of the whole problem, right?

jimthompson5910 (jim_thompson5910):

yes it is

OpenStudy (anonymous):

Ok thanks. i have one more questions. When constructing a an angle bisector, why must the arcs intersect?

jimthompson5910 (jim_thompson5910):

is that all it asks?

jimthompson5910 (jim_thompson5910):

or is there more to it?

OpenStudy (anonymous):

The last one is the one i just posted about the angles. ^^^

OpenStudy (anonymous):

for 100 + -4 im getting 96 now instead on 104?

jimthompson5910 (jim_thompson5910):

it should be 100 + 4 = 104

jimthompson5910 (jim_thompson5910):

not sure how you 100 + -4

OpenStudy (anonymous):

so that 4 shouldn't be a negative? and i got it from (-2)^2 =-4

OpenStudy (anonymous):

and i got that from 1-3^2

jimthompson5910 (jim_thompson5910):

(-2)^2 is positive 4, not negative 4

OpenStudy (anonymous):

Sorry, my mistake. Did you see the other question i posted?

OpenStudy (anonymous):

Also i got that -4 from a calulator, it keeps saying (-2)^2 is -4

jimthompson5910 (jim_thompson5910):

that's because you said -2^2 you should explicitly type in the parenthesis to say (-2)^2 = 4

OpenStudy (anonymous):

Oh ok, i got it now. Did you see the other question?

OpenStudy (anonymous):

Is it because of the vertex?

jimthompson5910 (jim_thompson5910):

I think it's because the two arcs must intersect to form that new point that's needed to draw the angle bisector

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