49^(x+1)=square root of 7?

Question

ness9630 · Answer

Get common bases, make both have a base of 7.

campbell_st · Answer

well  rewrite each side of the equation in index form with the same base

$$(7^2)^{(x + 1)} = 7^{\frac{1}{2}}$$

which simplifies to 

$$7^{2x + 2} = 7 ^{\frac{1}{2}}$$

now just equate the powers and solve for x

anonymous · Answer

its $$\sqrt{7}$$ not 7 $$\frac{ 1 }{ 2 } $$

campbell_st · Answer

well well a little index information 

$$\sqrt{7} = 7^{\frac{1}{2}}$$

to test it get a calculator and find 

$$\sqrt{7} =$$

next, using the power key on your calculator find 

$$7^{\frac{1}{2}}.... or.... 7^{0.5}$$

what happens...

anonymous · Answer

oh!! okay so now ive got 2x+2 =$$\frac{ 1 }{ 2 }$$
now what?

campbell_st · Answer

solve for x

akashdeepdeb · Answer

@shaa 
Need help?

anonymous · Answer

I got -1.25! that's wrong!

anonymous · Answer

yes please explain!

akashdeepdeb · Answer

Hold on for a sec...
The answer should be.....

akashdeepdeb · Answer

Is there an option such as -3/4?

anonymous · Answer

Ive got no options

campbell_st · Answer

well the answer may need to be in fraction form to start

so 2x + 2 = 1/2

subtract 2

2x = -3/2

akashdeepdeb · Answer

-0.75 ?

akashdeepdeb · Answer

Okay follow him. :D

anonymous · Answer

so the answer is -1.75?

campbell_st · Answer

no... 

you have 

2x = -3/2

divide both sides of the equation by 2

x = -3/4

to check if its correct, substitute into the original equation...

anonymous · Answer

-0.75 I mean

anonymous · Answer

sorry I typed it wrong haha! its -0.75 right?

campbell_st · Answer

well i'd probably write the answer is -3/4... but otherwise you're correct

anonymous · Answer

finally! thanks so much for your help! :)

campbell_st · Answer

good luck with your maths