Find two unit vectors orthogonal (perpendicular) to both the given vectors:
<1, -1, 1> <0, 4, 4>
find the det.
i was thinking a cross product meself
ahh, "determinant" ... yeah
oh yeah, cross product. Lol. if it equals 1, it's orthogonal.
My work: Found determent of following matrix: i j k 1 -1 1 0 4 4 \[=-8i -4j + 4k\] and: i j k 0 4 4 1 -1 1 \[=8i + 4j - 4k\] So, translate to unit vectors you should have: <-1, -1, 1> and <1, 1, -1>
8,4,4 doesnt reduce to 1,1,1
unit vector
and 1,1,1 is sqrt3 long, not 1 long
ah, that's probably what I'm doing wrong..
<1, -1, 1> <0, 4, 4> x 0 1 y 4 -1 z 4 1 x = (4--4) y = -(0-4) z = (0-4) (8,4,-4) is normal to both ... we can reduce by a factor of 4 (2,1,-1) , now divide it by its length
+- (2,1,-1) ---------- sqrt6
thanks
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