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Prove A-(A-B)=B-(B-A)
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For Set theory
Of course I need to show forward and converse. I also started the forward with "Let be x within A-(A-B)."
not sure where to go from there...
So by definition, x is in A, but x is not in A-B. So x must be in B as well. Now since x is in A, x is not in B-A. Hence x is in B-(B-A). Now go the other way!
hmm that was quite simple. *face palm*
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Thanks
@Erin001001 Thanks!
No problem :) What you really needed was a picture: with a Venn diagram and a bit of shading, it should be fairly easy to show that is x is in the LHS it must be in \(A \cap B\).
I started with a Venn diagram and then got to the proof and couldn't see how to relate the two expressions.
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