Find four consecutive odd integers whose sum is 232.
I used the guess and check method, so I know the answer. However, I was wondering if anyone knew the formula. :)

Question

Find four consecutive odd integers whose sum is 232. 
I used the guess and check method, so I know the answer. However, I was wondering if anyone knew the formula. :)

anonymous · Answer

Four consecutive odd integers, eh?

Let $x$ be the first of these odd integers. The next odd integer is thus $x+2$, and the next is $x+4$, and the last is $x+6$.

The sum of all four of these is 232, so you have
$$x+x+2+x+4+x+6=232\
4x+12=232$$
solve for $x$.

anonymous · Answer

x can be even sith lord

jamierox4ev3r · Answer

Thank you @SithsAndGiggles . I will use the formula to see if it works; I  already know the answer by guessing and checking (lol), thanks for providing an actual formula

anonymous · Answer

@thisSucks, in that case, let $x=2n+1$. Replace all the x's, and solve for $n$, then plug into $x=2n+1$ and solve for $x$.

anonymous · Answer

yeah 2n+1 looks correct @SithsAndGiggles I am Lord Kaan