Differentiate 2[f(x)^3] with respect to x
I'm trying to see why it comes out to \[\Large 6[f(x^2)]f \prime (x) \] and not \[\Large 6[f(x)^2]\]
@amistre64
@Hero
\[\frac{ d }{dx }\left\{ f ^{n} \left( x \right) \right\}=nf ^{n-1}\left( x \right)f'\left( x \right)\] \[\frac{ d }{ dx }f \left( x ^{n} \right)=f'\left( x ^{n} \right)n x ^{n-1}\]
because of the chain rule
Is it like that cause of "the respect to x" why it's like that?
i think you want the proof for chain rule
you must work it out from first principles
Yes, please lol. I just started calc and Im asking this question from here: http://www.wikihow.com/Take-Derivatives-in-Calculus
okay well lets start with stating the chain rule first and then we will prove it
Ok
|dw:1378419231311:dw|
Join our real-time social learning platform and learn together with your friends!