Question

At what height does a 1000-kg mass have a potential energy of 1 J relative to the ground? Show your work.

Answer 1

Are we trying to find the gravitational work on the 1000kg mass?

Answer 2

Tbh I have no idea whatsoever >.< lol

Answer 3

Potential Energy is:\[E_p=m·g·h \rightarrow h=\frac{ E_p }{ m·g }=\frac{ 1 }{ 1000·9.81 }=0.0001m\]and 0.0001m=0.1 mm

Answer 4

I don't understand what I'm supposed to plug into that eaquation

Answer 5

It really depends on how you want to calculate it.

For most cases we use newton's law of universal attraction to calculate the work, but in this case Gravitational Energy = mass * gravitational constant * height will do.

This question wants us to find height.
We have mass = 1000kg, E = 1J, and g = 9.81m/s^2, since we are dealing with on earth.

Putting it all together should give you the solution stated by CarlosGP

Answer 6

\[1_{p} = 1000kg \times 9.81m \div s ^{2} \times h \rightarrow h = \frac{ 1 _{p} }{1000kg \times 9.81m/s ^{2} }\]


Is that even close to a start

Answer 7

Yes, but there is no subscript p, but there should the the unit of Joule, which is actually: kg (m/s)^2, putting it all together h has the unit of m as expected.

Answer 8

Can I please see the correct order please? I'm slightly confused with the second part of what you just said.

Answer 9

Maybe in a few days, I tried typing it out in TeX twice but it crashed, taking everything I typed with it.

Answer 10

Okay then... thank you for trying T:

Answer 11

@AngelCriner Go back to the formula I wrote:
Ep=Potential Energy in Joules
h=height in meters
m=mass in Kilograms
g=9.81 m/sec^2

Answer 12

\[1J=1000kg \times 9.81m/\sec^2 \times ? \rightarrow ? = \frac{ 1J }{ 1000 \times 9.81 } = \frac{ 1}{ 1000 \times 9.81 } = 0.0001m\]

I am extremely lost

Answer 13

? = h = height in meters

Answer 14

I didn't know where the height came from though so I didn't have a number to plug in >.<

Answer 15

Work is force x distance, and the unit is joule (energy)
force is mass x acceleration, and unit is newton (force)
acceleration has units of m/s^2

square brackets means units of:
\[ [Energy] = J = [Force]*[Distance] = [mass]*[accleration]*[dist] = kg * m / s^2 * m\]
which simplifies to:
\[ J = kg * m^2/s^2\]

Substituting this J into the original expression you get height in units of meters, as it should be.

Answer 16

Read the problem and note that height is precisely the unknown you need to calculate

Answer 17

Oh.My.Goodness. >_\ Oh...my...GOODNESS.
I'm so sorry >.< I'm failing to understand the correlation between the problem and the expression. /: