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Chemistry 8 Online
OpenStudy (vane11):

Help please! Question attached as pic

OpenStudy (vane11):

OpenStudy (aaronq):

to find the rate, simply plug in the values into the rate law given. The overall rate order is the addition of the exponents (n,m) in the rate law: \(rate=k[A]^n[B]^m\) rate order= n+m

OpenStudy (vane11):

is not .024 right? cuz that seemed too easy to be true...

OpenStudy (aaronq):

yeah that's it.

OpenStudy (aaronq):

don't forget the units though.

OpenStudy (vane11):

wow that was way too easy haha and the units are already there for me but I'll rmember for my exam

OpenStudy (aaronq):

yeah, it was a simple plug and chug. good stuff.

OpenStudy (vane11):

quick question, would the rate order be 2 since [O3] has 1 and [NO] also has 1, or am I supposed to do some math to figure it out?

OpenStudy (aaronq):

no, it's that simple.

OpenStudy (vane11):

wow... ok

OpenStudy (aaronq):

lol

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