Question

What is the domain of f(x) = 1/sqrt x -3? Helpp!!

Answer 1

Is it\[f(x) = {1 \over \sqrt{x-3}}\]

Answer 2

yes!

Answer 3

then do the same as before... however, exclude the value(s) of x that will make the denominator zero. :D

Answer 4

I did do the same as before and I got the answer wrong

Answer 5

let's see. how did you do it?

Answer 6

You can not have negative values, it is not a real solution for the 
Also, not any values in which make the denominator equal to 0.So , x must be greater than or equal to 0.
x is all real numbers greater than 0, but 9.

Answer 7

If not to use complex then
x>3

Answer 8

I got 3, infinity

Answer 9

fter I redid it

Answer 10

@KenLJW is right.

Answer 11

can someone show me how they got their answer

Answer 12

by inspection
x<3 negative under the radical therefore complex
x=3 denominator is zero therefore undefined

Answer 13

i see