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Mathematics 19 Online
OpenStudy (anonymous):

vectors

OpenStudy (anonymous):

find two vectors such that mag(u+v)=mag(u) + mag(v) find two vectors such that mag(u-v)=mag(u) - mag(v)

OpenStudy (anonymous):

if you make u+v the reflection of u about an axis then you'll have the sum part taken care of.

OpenStudy (anonymous):

can you please provide me an example

OpenStudy (anonymous):

oops, i spoke to soon... just a sec.

OpenStudy (anonymous):

this has to do with the triangle inequality... ||a||+||b||>=||a+b|| so equality is only with 0 vector or if a & b point in the same direction.

OpenStudy (anonymous):

oh makes sense plz go ahead

OpenStudy (anonymous):

oops, goofed again as the inequality should be the other way round, i.e., ||a+b||<=||a||+||b|| sorry.

OpenStudy (anonymous):

can you provide me an example of u and v where this actually happens

OpenStudy (anonymous):

sure... u = <1, 0>, v = <1, 0>, u+v = <2, 0>

OpenStudy (anonymous):

arent u and v same vectors

OpenStudy (anonymous):

same work for the other one you're looking for. u - v = <0, 0> and ||u|| - ||v|| = 0

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

but the question is asking for 2 different vectors and the mag (u+v) =2 and mag(u) + mag(v) =4 in your example is not true

OpenStudy (anonymous):

if they can't be the same then let u = <1, 0>, v = <2, 0> and u+v = <3, 0> but equality of magnitudes still holds

OpenStudy (anonymous):

wrong. ||u|| = ||v|| = 1, ||u+v||= 2

OpenStudy (anonymous):

iin example where u = v.

OpenStudy (anonymous):

oh ya my bad mag (u+v) =4 and mag(u) + mag(v) =2 still doesnt equals

OpenStudy (anonymous):

mag(u+v) = 2 sqrt(2^2 + 0^2) = sqrt(4) = 2

OpenStudy (anonymous):

oops sorry :(

OpenStudy (anonymous):

it's okay. it's late and i'm tired enough for both of us

OpenStudy (anonymous):

hey just a sec the second ex you provided which has two difeerent vector has different magnitudes and they do not equal 1 + sqrt(2) is not equal to 3

OpenStudy (anonymous):

never mind i got your point can you plz show me ex of u-v sorry again

OpenStudy (anonymous):

only way it happens for that one is the same way... u & v must point in the same direction.

OpenStudy (anonymous):

however, ||u|| >=||v|| because ||u-v||>=0

OpenStudy (anonymous):

alright so u = 1,0 and v = -2,0 so u+v = -1,0 oh this dooesn't work

OpenStudy (anonymous):

wait no it does i guess u + v = 3,0 am i right

OpenStudy (anonymous):

they point in opposite directions

OpenStudy (anonymous):

so what example do you think would do u-v property true

OpenStudy (anonymous):

similar example... u = <2, 0>, v = <1, 0> u-v = <1, 0> ||u|| = 2, ||v|| = 1, ||u-v|| = 1

OpenStudy (anonymous):

great thank you

OpenStudy (anonymous):

you're welcome

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