Describe the solutions of y' =3xy^1/3
again it uses separate variables. attachment coming

Question

Describe the solutions of y' =3xy^1/3
again it uses separate variables. attachment coming

anonymous · Answer

Obviously you divide both sides by $y^{1/3}$

anonymous · Answer

Integrate both sides with respect to $x$ first.  Then replace $y'dx$ with $dy$.

anonymous · Answer

Don't do any of that multiply $dx$s and $dy$s around.  I can't stand that crap.

usukidoll · Answer

attachment

usukidoll · Answer

blame the vintage book. seriously last minute prof change...but the prof isn't bad. It's just that the book is coo coo. I think reading it super hard is worth it

anonymous · Answer

That's good.  Then just solve for $y$.

usukidoll · Answer

solve for y meaning... like divide everything by 3/2? or just multiply everything by the 3/2

abb0t · Answer

Integrate both sides and solve for $\sf \color{red}{y}$!

abb0t · Answer

Get the solution in the form y(x) = f(x) + C$_1$ or something like that.

usukidoll · Answer

alright...I did integrate...just need to solve for the y since it has 3/2y^2/3-3/2x^2 =c

usukidoll · Answer

|dw:1378453716677:dw|