spherical shell of inside radi. a and outside radi. b, b>a,has a spherically symmetric volume charge densi.ρ(r)=k/r² for a
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Well.. to calculate the electric field at any point outside the shell is pretty easy.. so ll leave that up to you Inside the shell is zero.. cause no charge is enclosed.. but at any random point p at a distance r from the centre such that a<r<b.. |dw:1378621766515:dw| apply Gauss law \[ \int\limits_{}^{}\bar E.\bar {dA}= \frac{Q_{enc}}{\epsilon_0}\] Due to symmetry.. the dot product vanishes, and you get E out.. and you can easily evaluate that trivial integral.. what now is Q_enc? well \[\sigma = \frac{dQ}{dv}\] or \[Q = \int\limits \sigma dv\] can u calculate further?!
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