Question

help pleaseeee @giligails @UnkleRhaukus

Answer 1

u knw how to complete the square ?

Answer 2

kinda

Answer 3

good :) try completing the square

\(y = x^2-6x+14 \)

Answer 4

change that to the form,

\(y = a(x-h)^2 + k \)

k is the required y coordinate of vertex

Answer 5

\(y = x^2-6x+14 \)

\(y = x^2-2(3)x+9+5 \)

\(y = (x-3)^2+5 \)

Answer 6

your just simplifying right?

Answer 7

ive just completed the square, now compare it wid
\(y = a(x-h)^2 + k\)

Answer 8

k is the required y-coordinate of the vertex

Answer 9

its 5

Answer 10

y=x^2-6x+14 implies y=(x-3)^2+5 thus the equation transforms as (y-5)=(x-3)^2
the vertex is (3,5)

Answer 11

5 = \(\checkmark\)

just may be have a look at how to complete the square and make urself convinced the final equation we got is correct :)

Answer 12

so i just put 5 ?

Answer 13

yep !

Answer 14

thanks so much:)

Answer 15

np :)