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Mathematics 18 Online
OpenStudy (anonymous):

lim(x->0) (sin8x)/x^2

OpenStudy (anonymous):

Could simplyify it?

OpenStudy (raden):

lim(x->0) (sin8x)/x^2 = lim(x->0) (sin8x)/x * 1/x = lim(x->0) (sin8x)/x * lim(x->0) 1/x = lim(x->0) 8(sin8x)/8x * lim(x->0) 1/x = 8 lim(x->0) (sin8x)/8x * lim(x->0) 1/x = 8 * 1 * 1/0 = 8/0 = infinity

OpenStudy (anonymous):

Thank you very much I see why this is correct now!

OpenStudy (raden):

you're welcome

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