Question

please help me!!
Solve for x and express roots in a + bi form:
x^2/4 = 2x-10
and can you tell me how you got it?

Answer 1

do you want to solve
\[\frac{ x ^{2} }{4 }=2x-10\]

Answer 2

yes

Answer 3

\[x ^{2}=8x-40\]
\[x ^{2}-8x=-40\]
complete the squares by adding(co-efficient of x/2)^2

Answer 4

i forgot how to complete the squares

Answer 5

i told you add(-8/2)^2 ,i.e., 16

Answer 6

ohhh thanks

Answer 7

show me your work if any difficulty i will guide you.

Answer 8

x^2 - 8x + 16 = -24

Answer 9

write L.H.S as (a-b)^2 and R.H.S -1*24

Answer 10

\[\left( x-4 \right)^{2}=4*6*-1=4*6*\iota ^{2}=\left( 2\sqrt{6}\iota \right)^{2}\]

Answer 11

\[x-4=\pm 2\sqrt{6}\iota \]
now write the two values of x

Answer 12

x = \[4\pm 2i \sqrt{6}\]

Answer 13

these are two solutions one with + sign and the other negative sign.

Answer 14

\[x=4+2\sqrt{6}\iota ,and x=4-2\sqrt{6}\iota \]

Answer 15

okay. i get it now. thank you so much!

Answer 16

yw