Question

I need some help figuring out if this is always, sometimes, or never true?

Answer 1

6+8x-9=11x+14-3x (Equation)
+3x +3x
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6+8x-9=14x+14
+9 +9
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15+8x=14x+14
-14 -14
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1+8x=14x
-8x -8x
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1=4x

So what do i do next?

Answer 2

\[\Large 6+8x-9 \quad=\quad 11x+14-3x\]This is what we're starting with?
Hmm looks like you made an error on the first step maybe.
Adding 3x to each side should give us,\[\Large 6+8x-9\color{royalblue}{+3x} \quad=\quad 11x+14-3x\color{royalblue}{+3x}\]Which simplifies to,\[\Large 6+11x-9 \quad=\quad 11x+14\]

Answer 3

I just added it so i could isolate the variable. i took it off one side and did the same function to the other side

Answer 4

You didn't add it to the other side though. Do you see where your equals sign is?
You added 3x to the same side twice.

Answer 5

i was just putting them together so i could take them from one side in one step instead of two

Answer 6

i was putting 11x and 3x together

Answer 7

I don't understand.. :c hmm

Answer 8

You can't put the 3x with the 11x and ALSO put the 3x with the -3x.
Do you understand what I mean?

You end up adding 6x when you do that.

Answer 9

there were two values on the same side with the same variable so I combined them

Answer 10

So you combine the 11x and -3x?
That would give you 8x on the right side.

Answer 11

oh ok i see what you mean

Answer 12

Try again from that step! :D

Answer 13

i got x=-17

Answer 14

\[\Large 6+8x-9 \quad=\quad 11x+14-3x\]The first step, combining the 11x and -3x gives us,\[\Large 6+8x-9 \quad=\quad 8x+14\]Our next step should be to `subtract` 8x from each side.

Answer 15

Leaving us with,\[\Large 6-9=14\]Understand what I did there? :o

Answer 16

yep i see what you did

Answer 17

So if you simplify the left side all the way down, what do you get? :D
And `when` is that statement true?

Answer 18

-3=14

Answer 19

It is never true, is it?

Answer 20

Good job! :)

Correct, -3 is never equal to 14.

Answer 21

Thanks