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Physics 12 Online
OpenStudy (anonymous):

Im having trouble figuring this out too Calculate the worst case uncertainty in P as follows: first calculate one extreme of P by using L=26 cm and W=16 cm. Then calculate the other extreme using L=24 cm and W=14 cm. The worst case spread is the difference in these two extreme values of P. Set this spread equal to 2 sigmaP and calculate sigmaP. What i did so far p1= 2(26) +2(14)=84 cm p2= 2(26) +2(24)= 80 cm 84-80=4 cm idk what to do from here 40 minutes ago - 4 days left to answer. Additional Details is it 2Sigmap= 4 cm Sigmap= 2cm ?

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