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Mathematics 17 Online
OpenStudy (anonymous):

HELP MY FRIEND!!!

OpenStudy (anonymous):

what do you need help on?

OpenStudy (anonymous):

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OpenStudy (anonymous):

so you are trying to find g(x)?

OpenStudy (anonymous):

Trying to find g(f(x))

OpenStudy (anonymous):

oh..... did you try to set them equal to each other?

OpenStudy (anonymous):

your not trying to find them by themselves, you are trying to find f(x) within g(x)

OpenStudy (anonymous):

you should ask @DebbieG for help they might be able to help you

OpenStudy (anonymous):

sorry i couldn't help you much :(

OpenStudy (debbieg):

So you want g(f(x)), given that \(\Large f(x)=x^2-3\\ \Large g(x)=x^2+1\) Remember what function notation means: it means that you "plug in" whatever is in the ( ) for the variable in the definition of the function, right? E.g. if \(\Large g(x)=x^2+1\\ \text{then } \Large g(6)=6^2+1\\ \text{and } \Large g(a)=a^2+1\\ \text{and } \Large g(r+1)=(r+1)^2+1\\\) Right? So to find \(\Large g(f(x))\) you'll just want to plop \(f(x)\) into \(g(x)\) in place of the variable x, and simplify the resulting expression: \(\Large g(f(x))=g(x^2-3)=(x^2-3)^2+1\) Expand that product and add like terms.

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