How do you factor 4q^2-19q+12
I can get to this but I don't know what to about the -19. (2q 6)+(2q 2)
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OpenStudy (yamyam70):
hi :) first multiply 4 and 12 :)
OpenStudy (anonymous):
hi ok I get 48
which could possibly be -2 x24
OpenStudy (anonymous):
but how to make that equal -19
OpenStudy (yamyam70):
okay, next step is to get the factor pairs of 48, that when you add it the result is -19 :)
OpenStudy (yamyam70):
what do you think would be the 2 factors?
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OpenStudy (anonymous):
that's where I am getting stuck
OpenStudy (yamyam70):
try -16, -3
OpenStudy (anonymous):
that works
thak you
OpenStudy (anonymous):
*thank
OpenStudy (yamyam70):
so what would be your factors?
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OpenStudy (anonymous):
-16 *-3
OpenStudy (anonymous):
(2q-166)+(2q-32)
OpenStudy (yamyam70):
aha, what would be your final answer ?
OpenStudy (yamyam70):
that is not a factor :) ,that is addition, which likely you will combine like terms :)
OpenStudy (anonymous):
4Q(-198)
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OpenStudy (anonymous):
here
OpenStudy (yamyam70):
1q-4(4q-3) is correct :)
OpenStudy (anonymous):
Thank you for the explanation now I get how to do it. I tried another site and all they wanted to do is give me the answer which doesn't really help me learn
OpenStudy (yamyam70):
What I do is, I factor by grouping, do you want me to teach you that ? :)
OpenStudy (anonymous):
if you don't mind
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OpenStudy (yamyam70):
You're welcome :)
OpenStudy (yamyam70):
Okay here goes
OpenStudy (anonymous):
Yeap np that method is called the umbrella method, easiest to learn until you learn how to just look at the problem and get the answer
OpenStudy (yamyam70):
4q^2-19q + 12 * first we multiply 4 and 12
we get 48, our goal is to find
factors of 48 , that when we combine them
we get -19 q , follow?
OpenStudy (anonymous):
yes
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OpenStudy (yamyam70):
our factor pair is , -16 and -3 , which will give us -19 :)
OpenStudy (anonymous):
that makes it seem easy now.
OpenStudy (yamyam70):
so when grouping ,
it goes like this , . . 4q^2 -16q -3q +12
-16 and -3 are our factors :)
OpenStudy (yamyam70):
we just expanded -19q :)
OpenStudy (anonymous):
yes expanded it so that it would be a factor of both numbers
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OpenStudy (yamyam70):
aha!
OpenStudy (yamyam70):
so by grouping we take the GCF of the First Two terms.
OpenStudy (yamyam70):
and we do the same for the other 2 terms :)
OpenStudy (anonymous):
I wrote it down so I wont forget it. Thanks
now to figure out how to do this one 2(a+b)^2-5(a+b)-3
OpenStudy (yamyam70):
what are we trying to do?
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OpenStudy (anonymous):
same thing factor it out completely
OpenStudy (yamyam70):
I see.
OpenStudy (yamyam70):
one moment :)
OpenStudy (anonymous):
(a+b^2 +a+b)-6
OpenStudy (yamyam70):
what do you think should be done first? exponent or constant?
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OpenStudy (yamyam70):
is that what we are trying to factor?
OpenStudy (anonymous):
no I was trying to figure it out 2(a+b)^@+(a+b)-6 I think I should athe a+b together correct
OpenStudy (anonymous):
^2
OpenStudy (yamyam70):
we have an exponent ^2
OpenStudy (anonymous):
yes on the first a +b
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OpenStudy (yamyam70):
yup, so we can't combine
OpenStudy (yamyam70):
to be honest I'm quite rusty on this, lol I'll seek help for you :)
OpenStudy (anonymous):
ok I need all the help I can get:)
OpenStudy (yamyam70):
@DebbieG We may need your help :)
OpenStudy (anonymous):
the problem is 2(a+b)^2-5(a+b)-3
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OpenStudy (yamyam70):
uhmm red, I'm going to bed as, I have class tommorow, so nice time with you :) night