Ask your own question, for FREE!
Algebra 13 Online
OpenStudy (anonymous):

How do you factor 4q^2-19q+12 I can get to this but I don't know what to about the -19. (2q 6)+(2q 2)

OpenStudy (yamyam70):

hi :) first multiply 4 and 12 :)

OpenStudy (anonymous):

hi ok I get 48 which could possibly be -2 x24

OpenStudy (anonymous):

but how to make that equal -19

OpenStudy (yamyam70):

okay, next step is to get the factor pairs of 48, that when you add it the result is -19 :)

OpenStudy (yamyam70):

what do you think would be the 2 factors?

OpenStudy (anonymous):

that's where I am getting stuck

OpenStudy (yamyam70):

try -16, -3

OpenStudy (anonymous):

that works thak you

OpenStudy (anonymous):

*thank

OpenStudy (yamyam70):

so what would be your factors?

OpenStudy (anonymous):

-16 *-3

OpenStudy (anonymous):

(2q-166)+(2q-32)

OpenStudy (yamyam70):

aha, what would be your final answer ?

OpenStudy (yamyam70):

that is not a factor :) ,that is addition, which likely you will combine like terms :)

OpenStudy (anonymous):

4Q(-198)

OpenStudy (anonymous):

here

OpenStudy (yamyam70):

1q-4(4q-3) is correct :)

OpenStudy (anonymous):

Thank you for the explanation now I get how to do it. I tried another site and all they wanted to do is give me the answer which doesn't really help me learn

OpenStudy (yamyam70):

What I do is, I factor by grouping, do you want me to teach you that ? :)

OpenStudy (anonymous):

if you don't mind

OpenStudy (yamyam70):

You're welcome :)

OpenStudy (yamyam70):

Okay here goes

OpenStudy (anonymous):

Yeap np that method is called the umbrella method, easiest to learn until you learn how to just look at the problem and get the answer

OpenStudy (yamyam70):

4q^2-19q + 12 * first we multiply 4 and 12 we get 48, our goal is to find factors of 48 , that when we combine them we get -19 q , follow?

OpenStudy (anonymous):

yes

OpenStudy (yamyam70):

our factor pair is , -16 and -3 , which will give us -19 :)

OpenStudy (anonymous):

that makes it seem easy now.

OpenStudy (yamyam70):

so when grouping , it goes like this , . . 4q^2 -16q -3q +12 -16 and -3 are our factors :)

OpenStudy (yamyam70):

we just expanded -19q :)

OpenStudy (anonymous):

yes expanded it so that it would be a factor of both numbers

OpenStudy (yamyam70):

aha!

OpenStudy (yamyam70):

so by grouping we take the GCF of the First Two terms.

OpenStudy (yamyam70):

and we do the same for the other 2 terms :)

OpenStudy (anonymous):

I wrote it down so I wont forget it. Thanks now to figure out how to do this one 2(a+b)^2-5(a+b)-3

OpenStudy (yamyam70):

what are we trying to do?

OpenStudy (anonymous):

same thing factor it out completely

OpenStudy (yamyam70):

I see.

OpenStudy (yamyam70):

one moment :)

OpenStudy (anonymous):

(a+b^2 +a+b)-6

OpenStudy (yamyam70):

what do you think should be done first? exponent or constant?

OpenStudy (yamyam70):

is that what we are trying to factor?

OpenStudy (anonymous):

no I was trying to figure it out 2(a+b)^@+(a+b)-6 I think I should athe a+b together correct

OpenStudy (anonymous):

^2

OpenStudy (yamyam70):

we have an exponent ^2

OpenStudy (anonymous):

yes on the first a +b

OpenStudy (yamyam70):

yup, so we can't combine

OpenStudy (yamyam70):

to be honest I'm quite rusty on this, lol I'll seek help for you :)

OpenStudy (anonymous):

ok I need all the help I can get:)

OpenStudy (yamyam70):

@DebbieG We may need your help :)

OpenStudy (anonymous):

the problem is 2(a+b)^2-5(a+b)-3

OpenStudy (yamyam70):

uhmm red, I'm going to bed as, I have class tommorow, so nice time with you :) night

OpenStudy (anonymous):

thank you for the help

OpenStudy (yamyam70):

Just start another session :)

OpenStudy (yamyam70):

bye :)

OpenStudy (anonymous):

ok I will

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!