Question

A point charge q1 = -4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = +6.00 nC is at the point x = 0.60 m , y = 0.

Part A)Calculate the magnitude of the net electric field at the origin due to these two point charges

Part B)Calculate the direction of the net electric field at the origin due to these two point charges.

Answer 1

can you calculate the electric field due to each charges separately?

Answer 2

Can I do it? No, I understand that's what I think I have to do, but I just don't know how :/

Answer 3

how do you calculate electric field due to a charge Q at origin at point (x,y)

Answer 4

coulomb's law?

Answer 5

yes ... use coloumd law to calculate electric field.

Answer 6

first try my problem (it's easy) ... draw picture,
then we will try yours.

Answer 7

alright

Answer 8

what is your problem?

Answer 9

a charge of magnitude Q is at origin,
calculate electric field at (3,4)

Answer 10

Just to make sure is this the equation I have to use?

\[F = k (|q_1q_2|)/r^2\]

Answer 11

yes ... E = F/q

Answer 12

how do I find r? that's one of the things that has been confusing me

Answer 13

r= sqrt(x^2+y^2)

Answer 14

oooh

Answer 15

would it be:

\[F = ((9 x 10^9) (Q) )/ 5\]

Answer 16

that is 9 x 10^9

Answer 17

so, I'm guessing im wrong? :/

Answer 18

r^2

Answer 19

so would that be 25 instead of 5 then.

Answer 20

yes

Answer 21

is Electric Field scalar or vector?

Answer 22

vector

Answer 23

do you know that vector has components?

Answer 24

yea

Answer 25

how do you find the two components of this vector?

Answer 26

draw figure ...