Question

A line passes through (-4, 1), perpendicular to a line whose slope is -3/2 how am I supposed to graph it anyone could help

Answer 1

If two lines are perpendicular, their slopes are inverse opposites.
\(m_1=\dfrac{a}{b},~m_2=-\dfrac{b}{a}\)
And you also have the equation of a line (slope intercept form),
\(y=mx+b\)

Answer 2

Ok

Answer 3

Did that make sense?

Answer 4

Yea kinda

Answer 5

So if I plug it in like this... 1=-3/2x +(-4)

Answer 6

Wrong slope,
\(m_1=-\dfrac{3}{2},~m_2=~?\)

Answer 7

And you plugged in the x value into the "b" spot, you plug it in for "x".

Answer 8

How do u get to kno the slope of the other line?

Answer 9

I told you how to find it up above. Inverse opposite of the given slope.

Answer 10

Oooh so if the slope is negative I change it to inverse its positive?

Answer 11

No its not making any sense now explain in a different way if u can

Answer 12

Hello?

Answer 13

@hubbabubba :
When tow line are perpendicular we have :
m.m2=-1
So the slope is 2/3
And we have :
y=2/3x
But what is the (-4,1) ?
Look :
-4/1=-4
So we should be have d too .
Now can u answer d ?:)

Answer 14

Where did u get d from???

Answer 15

d is the piont the line and y .

Answer 16

Wait ...
What is the (-4,1)in the question ???

Answer 17

Its a line that passes thro tha point

Answer 18

It s a point ?

Answer 19

@hubbabubba

Answer 20

Yes

Answer 21

So its ok !
Now u should use this formula :
y-y2=m(x-x2)
X1=-4
Y2=1
OK?:)

Answer 22

K

Answer 23

So its gonna be

Answer 24

1 - y2 = -3/2 (-4 - x2) right?

Answer 25

Excelent but I said to you :
x2=-4
y2=1
2 is just a number no *2 ...

Answer 26

Ik it x2

Answer 27

Y x2 n y2

Y not x1 n y1

Answer 28

No diffrence 1or2 are just name .
you should get the things true in formula means get the (-4,1)of point than y and x not affter them !
Because your answer will be fall :)
Now answer again :)

Answer 29

Y - 1 = -3/2 ( x + 4 ) right?

Answer 30

Exelent !:)

Answer 31

Then y = -3/2x + 6 right? As in y=mx +b

Answer 32

But the slope was 2/3 forgot ?

Answer 33

Look :
y-1=2/3(x+4)
OK ??!:)

Answer 34

A line passes through (-4, 1), perpendicular to a line whose slope is -3/2.
\(m_1=-\dfrac{a}{b}=-\dfrac{3}{2}\)
\(m_2=-(-\dfrac{b}{a})=-(-\dfrac{2}{3})=\dfrac{2}{3}\)

Then we have the equation of a line, \(y=mx+b\)
With the point, \((-4,1)=(x,y)\) which we then plug into the equation to solve for the y intercept b.
\(y=mx+b\rightarrow1=(-4)(\dfrac{2}{3})+b\)
\(b=\dfrac{11}{3}\)

So therefore we have,
\(y=\dfrac{2}{3}x+\dfrac{11}{3}\)

Answer 35

Okay

Answer 36

@hubbabubba :Understand and got it ?

Answer 37

No

Answer 38

did u get my formula ?

Answer 39

How did u get 11/3 ? @ austinL

Answer 40

And no ur making it complicated for me btw @E.ali

Answer 41

How did u get 11/3 ? @ austinL

Answer 42

@austinL

Answer 43

You simply solve for b in that equation.

Answer 44

Dont think about 11/3 .
I m not sure about it :)
Can you write it by the formula ?

Answer 45

\(y=mx+b→1=(−4)(\dfrac{2}{3})+b\)

Answer 46

Yea i did that

Answer 47

Wat formula are u talking abt? Im taking algebra 2 here

Answer 48

@austinL : I think I m answering friend !:)

Answer 49

@hubbabubba
:about about it :y-1=2/3(x+4)
OK?

Answer 50

For the 3rd time I got the equation I solved it but it didnt give me 11/3

Answer 51

So u multiply ( -4 ) × 2/3 right?

Answer 52

\(-4\times(\dfrac{2}{3})=-\dfrac{8}{3}\)
\(1+\dfrac{8}{3}=\dfrac{3}{3}+\dfrac{8}{3}=\dfrac{8+3}{3}=\dfrac{11}{3}\)

Answer 53

Oh k makes sense now thnx austin

Answer 54

No problemo.

Answer 55

Ok then so how do I graph the equation n the point?