Solve the equation and check for extraneous equations. 9|9-8x|=2x+3 Help me please I am stuck on this question.
The absolute value can be written as \(|x|=x\) when \(x≥0\) and \(|x|=-x\) when \(x<0\). So you can split your equation in two by imposing conditions on each equation.
So what would be the answer? Im confused.
So when \(9-8x≥0\Leftrightarrow x≤\frac{9}{8}\) we have \(|9-8x|=9-8x\) and the other case, namely \(x>\frac{9}{8}\) we have \(|9-8x|=-(9-8x)=8x-9\). Put this in and solve both equations.
Then check that the solutions to those equations really satisfy the inequalities, otherwise you have found a extraneous solution (a solution that you got from these sub-problems but wasn't a solution to the original problem).
Im still confused all I really wanted was the answer
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