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Physics 12 Online
OpenStudy (anonymous):

a ball is thrown upward. what is its time interval between the release of the ball and the time it reaches its maximum height? the acceleration of gravity is 9.8 m/s2 and the maximum height is 3.6m. answer in s

OpenStudy (anonymous):

Use the following eqs respectively to obtain time t 1) v^2(final) - v^2(initial)=-2gh, (h=3.6m) 2) v(final) = -gt + v(initial) according to the fact that the final velocity of the particle would be zero at its maximum height, you can find its initial velocity. Then put initial velocity into eq 2 to obtain time t.

OpenStudy (anonymous):

how do you find the initial velocity?

OpenStudy (anonymous):

You can simply do by eq1, since final velocity is zero there.

OpenStudy (anonymous):

how do you know what equation to use if you are trying to figure out a problem that uses velocity?

OpenStudy (anonymous):

It mostly depends upon how much you do exercise everyday. Pick up several problems and try to solve them.

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

Anytime.

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