a ball is thrown upward. what is its time interval between the release of the ball and the time it reaches its maximum height? the acceleration of gravity is 9.8 m/s2 and the maximum height is 3.6m. answer in s
Use the following eqs respectively to obtain time t 1) v^2(final) - v^2(initial)=-2gh, (h=3.6m) 2) v(final) = -gt + v(initial) according to the fact that the final velocity of the particle would be zero at its maximum height, you can find its initial velocity. Then put initial velocity into eq 2 to obtain time t.
how do you find the initial velocity?
You can simply do by eq1, since final velocity is zero there.
how do you know what equation to use if you are trying to figure out a problem that uses velocity?
It mostly depends upon how much you do exercise everyday. Pick up several problems and try to solve them.
thanks!
Anytime.
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