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Mathematics 13 Online
OpenStudy (anonymous):

Find an equation in standard form for the ellipse with the vertical major axis of length 18, and minor axis of length 16.

OpenStudy (anonymous):

For the equation of a vertical ellipse use (y - k)²/a² + (x - h)²/b² = 1 where a ≥ b and the center is (h, k), thus the length of major axis = 2a and the length of minor axis = 2b

OpenStudy (anonymous):

I just do not know what to plug in.

OpenStudy (anonymous):

my answer isnt coming out right.. aparently i am not much help, sorry

OpenStudy (jdoe0001):

"standard form" for an ellipse, means, it's center is the origin pretty much now we know the vertical axis, is also the "major axis" that means that the ellipse is going vertically, that means that the HIGHER DENOMINATOR, that is, the "a" component goes under the "y" variable fraction so "a" and "b" are given, so, plug them in => \(\bf \cfrac{(y-k)^2}{a^2}+\cfrac{(x-h)^2}{b^2}=1\)

OpenStudy (anonymous):

18 is a, 16 is b, correct? Now, what would k and h be?

OpenStudy (jdoe0001):

---> "standard form" for an ellipse, means, it's center is the origin pretty much <---

OpenStudy (jdoe0001):

in equations notations, (h, k) usually stand for the center or vertex or pivot point of the graph

OpenStudy (jdoe0001):

what's the (h, k) of the origin? that's your center

OpenStudy (anonymous):

Sorry I'm back. H,K = (0,0)

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