lim as theta approaches 0 (cos theta-1)/sin theta
Multiply by the conjugate?
And welcome to openstudy btw :)
ohh ok so I would then multiply by cos theta + 1 ??
& thanks :))
Yup!
I was thinking multiplying by \(\dfrac{x}{x}\) would be simpler.
I doubt you know L'hopital? And won't they give you the same thing, Siths?
No I don't no L'hopital ? & umm let me try
Yes, but not if you separate the limits: \[\lim_{x\to0}\frac{\cos x-1}{\sin x}\cdot\frac{x}{x}=\color{blue}{\lim_{x\to0}\frac{\cos x-1}{x}}\cdot\color{red}{\lim_{x\to0}\frac{x}{\sin x}}\]
Sith, I don't think she's that far in calc :3 Let's just stick to the basics for now
lol i'm in cal 1
These limits are usually presented early on in the course. The blue is equivalent to 0, the red to 1.
oh so the answer would be 0 right? because they are being multiplied together
Pretty much, right?
Yes. Have you learned these limits yet?
not really :/ my professor briefly went over limits using trig functions so i'm confused :(
Don't worry, you got us :3
lol thanks :) I wasn't sure if this website was going to help :O
Trust me, it does. You just got to know the right people around here. @SithsAndGiggles is a great help around here
*cough* khan academy has great videos *cough*
Khan Academy? Pfft >.>
I have to go but I have some more questions where will I find you guys when I come back?
Probably on here still xD
lol ok hopefully!
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