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Precalculus 19 Online
OpenStudy (anonymous):

Evaluate the expression: v ⋅ w Given the vectors: r = <8, 1, -6>; v = <6, 7, -3>; w = <-7, 5, 2>

ganeshie8 (ganeshie8):

dot product

ganeshie8 (ganeshie8):

simply multiply the same components, and add them together v = <6, 7, -3>; w = <-7, 5, 2> v.w = 6(-7) + 7(5) + (-3)(2)

OpenStudy (usukidoll):

v = <v1,v2,v3....vn> w=<w1,w2,....wn> V dot W <v1w1+v2w2+v3w3....vnwn>

OpenStudy (usukidoll):

sdfjlsafj;j w = <w1,w2,w3....wn>

OpenStudy (anonymous):

wait im confuse

OpenStudy (usukidoll):

what I just typed is the standard format for a dot product. you had three terms in there and I accidentally typed 2 for the w... vectors have to be equal

OpenStudy (usukidoll):

your v was 6, 7, -3 right? v = <v1,v2,v3> so v1 = 6 v2 = 7 v3 = -3

OpenStudy (usukidoll):

w = <-7, 5, 2> w1 = -7 w2= 5 w3 = 2 since w = <w1,w2,w3>

OpenStudy (anonymous):

@UsukiDoll I agree.

OpenStudy (anonymous):

yes

OpenStudy (usukidoll):

so general dot product format will be u dot v or in your case v dot w = <v1w1+v2w2+v3w3> when I typed vnwn it's up to a number n

OpenStudy (usukidoll):

Therefore <6(-7)+7(5)+(-3)(2)>

OpenStudy (usukidoll):

<-42+35-6>

OpenStudy (anonymous):

oh okayy! :)

OpenStudy (anonymous):

do you further solve it?

OpenStudy (usukidoll):

I'm gonna try solve it without a calc.

OpenStudy (anonymous):

i got 1

OpenStudy (anonymous):

wait i mean -13

OpenStudy (usukidoll):

|dw:1378591826415:dw|

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